X^2+4x=2(x-1)

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Solution for X^2+4x=2(x-1) equation: 



X^2+4X=2(X-1)

We move all terms to the left:

X^2+4X-(2(X-1))=0



We calculate terms in parentheses: -(2(X-1)), so:

2(X-1)

We multiply parentheses

2X-2

Back to the equation:

-(2X-2)



We get rid of parentheses

X^2+4X-2X+2=0

We add all the numbers together, and all the variables

X^2+2X+2=0

a = 1; b = 2; c = +2;
Δ = b2-4ac
Δ = 22-4·1·2
Δ = -4
Delta is less than zero, so there is no solution for the equation

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